2019 AMC 10B Problems/Problem 3: Difference between revisions
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Thus there are <math>500-x = 220</math> non-seniors. Since 70% of the non-seniors play a musical instrument, <math>220 \cdot \frac{7}{10} = \boxed{\textbf{(B) } 154}</math>. | Thus there are <math>500-x = 220</math> non-seniors. Since 70% of the non-seniors play a musical instrument, <math>220 \cdot \frac{7}{10} = \boxed{\textbf{(B) } 154}</math>. | ||
~IronicNinja | |||
==Solution 2== | ==Solution 2== | ||
Revision as of 22:58, 17 February 2019
Problem
In a high school with
students,
of the seniors play a musical instrument, while
of the non-seniors do not play a musical instrument. In all,
of the students do not play a musical instrument. How many non-seniors play a musical instrument?
Solution 1
of seniors do not play a musical instrument. If we denote
as the number of seniors, then
Thus there are
non-seniors. Since 70% of the non-seniors play a musical instrument,
.
~IronicNinja
Solution 2
Let
be the number of seniors, and
be the number of non-seniors. Then
Multiplying both sides by
gives us
Also,
because there are 500 students in total.
Solving this system of equations give us
,
.
Since
of the non-seniors play a musical instrument, the answer is simply
of
, which gives us
.
Solution 3 (using the answer choices)
We can clearly deduce that
of the non-seniors do play an instrument, but, since the total percentage of instrument players is
, the non-senior population is quite low. By intuition, we can therefore see that the answer is around
or
. Testing both of these gives us the answer
.
See Also
| 2019 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
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