Art of Problem Solving

1995 USAMO Problems/Problem 5: Difference between revisions

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==See Also==
==See Also==
{{USAMO box|year=1995|num-b=1|num-a=3}}
{{USAMO box|year=1995|num-b=4|after=Last Problem}}
{{MAA Notice}}
{{MAA Notice}}
[[Category:Olympiad Combinatorics Problems]]
[[Category:Olympiad Combinatorics Problems]]

Revision as of 07:09, 19 July 2016

Problem

Suppose that in a certain society, each pair of persons can be classified as either amicable or hostile. We shall say that each member of an amicable pair is a friend of the other, and each member of a hostile pair is a foe of the other. Suppose that the society has $\, n \,$ persons and $\, q \,$ amicable pairs, and that for every set of three persons, at least one pair is hostile. Prove that there is at least one member of the society whose foes include $\, q(1 - 4q/n^2) \,$ or fewer amicable pairs.

Solution

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See Also

1995 USAMO (ProblemsResources)
Preceded by
Problem 4
Followed by
Last Problem
1 2 3 4 5
All USAMO Problems and Solutions

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