1962 AHSME Problems/Problem 16: Difference between revisions

Revision as of 21:56, 10 November 2013

Problem

Given rectangle $R_1$ with one side $2$ inches and area $12$ square inches. Rectangle $R_2$ with diagonal $15$ inches is similar to $R_1$ . Expressed in square inches the area of $R_2$ is:

$\textbf{(A)}\ \frac{9}2\qquad\textbf{(B)}\ 36\qquad\textbf{(C)}\ \frac{135}{2}\qquad\textbf{(D)}\ 9\sqrt{10}\qquad\textbf{(E)}\ \frac{27\sqrt{10}}{4}$

Solution

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Revision as of 21:45, 9 November 2013 view source Fadebekun (talk \| contribs) 300 edits Created page with "==Problem== Given rectangle <math>R_1</math> with one side <math>2</math> inches and area <math>12</math> square inches. Rectangle <math>R_2</math> with diagonal <math>15</math> ..."		Revision as of 21:56, 10 November 2013 view source Fadebekun (talk \| contribs) 300 edits →Solution Newer edit →
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	==Solution==		==Solution==
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1962 AHSME Problems/Problem 16: Difference between revisions

Revision as of 21:56, 10 November 2013

Problem

Solution