2007 AMC 8 Problems/Problem 2: Difference between revisions

Revision as of 11:47, 5 November 2017

Problem

$650$ students were surveyed about their pasta preferences. The choices were lasagna, manicotti, ravioli and spaghetti. The results of the survey are displayed in the bar graph. What is the ratio of the number of students who preferred spaghetti to the number of students who preferred manicotti?

$\mathrm{(A)} \frac{2}{5} \qquad \mathrm{(B)} \frac{1}{2} \qquad \mathrm{(C)} \frac{5}{4} \qquad \mathrm{(D)} \frac{5}{3} \qquad \mathrm{(E)} \frac{5}{2}$

Solution

The answer is $\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}$

So,

$\frac{250}{100}$

Simplify,

$\frac{5}{2}$

The answer is $\boxed{\textbf{(E)}\ \dfrac{5}{2}}$

2007 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing

@@ Line 8: / Line 8: @@
 == Solution ==
-The answer is (number of students who preferred spaghetti)/(number of students who preferred manicotti)
+The answer is <math>\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}</math>
 So,

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2007 AMC 8 Problems/Problem 2: Difference between revisions

Revision as of 11:47, 5 November 2017

Problem

Solution

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