2011 AMC 10B Problems/Problem 14: Difference between revisions
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== Problem | == Problem== | ||
A rectangular parking lot has a diagonal of <math>25</math> meters and an area of <math>168</math> square meters. In meters, what is the perimeter of the parking lot? | A rectangular parking lot has a diagonal of <math>25</math> meters and an area of <math>168</math> square meters. In meters, what is the perimeter of the parking lot? | ||
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\end{align*}</cmath> | \end{align*}</cmath> | ||
The perimeter of a rectangle is <math>2 (a + b) = 2 (31) = \boxed{\textbf{(C)} 62}</math> | The perimeter of a rectangle is <math>2 (a + b) = 2 (31) = \boxed{\textbf{(C)} 62}</math> | ||
== See Also== | |||
{{AMC10 box|year=2011|ab=B|num-b=13|num-a=15}} | |||
Revision as of 16:14, 4 June 2011
Problem
A rectangular parking lot has a diagonal of 
meters and an area of 
square meters. In meters, what is the perimeter of the parking lot?
Solution
Let the sides of the rectangular parking lot be 
and 
. Then 
and 
. Add the two equations together, then factor.
The perimeter of a rectangle is 
See Also
| 2011 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
