2024 AMC 8 Problems/Problem 1: Difference between revisions
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== Video by MathTalks_Now == | == Video by MathTalks_Now == | ||
<cmath>boxed{\textbf{https://www.youtube.com/watch?v=crn37TRMLv4}}</cmath> | <cmath> \boxed{\textbf{https://www.youtube.com/watch?v=crn37TRMLv4}} </cmath> | ||
-rc1219 | -rc1219 | ||
Revision as of 16:11, 19 January 2025
Problem
What is the last digit of:
Solution 1
We can rewrite the expression as
. We note that the units digit of
is
because all the units digits of the five numbers are
and
, which has a units digit of
. Now, we have something with a units digit of
subtracted from
, and so the units digit of this expression is
.
Solution 2
So our answer is
.
Solution 3
We only care about the units digits. Thus,
ends in
,
after regrouping(10-2) ends in
,
ends in
,
ends in
, and
ends in
.
Solution 4
We just take the units digit of each and subtract, adding an extra ten to the first number so we don't get a negative number:
Video by MathTalks_Now
-rc1219
Solution 5
Video Solution 1 (Detailed Explanation) 🚀⚡📊
Youtube Link ⬇️
~ ChillGuyDoesMath :)
Video Solution by Central Valley Math Circle (Goes through full thought process)
Video Solution 2 (MATH-X)
https://youtu.be/BaE00H2SHQM?si=O0O0g7qq9AbhQN9I&t=130
Video Solution 3 (A Clever Explanation You’ll Get Instantly)
https://youtu.be/5ZIFnqymdDQ?si=IbHepN2ytt7N23pl&t=53
Video Solution 4 (Quick and Easy)
Video Solution 5 Interstigation
https://youtu.be/ktzijuZtDas&t=36
Video Solution 6 Daily Dose of Math
https://youtu.be/bSPWqeNO11M?si=HIzlxPjMfvGM5lxR
Video Solution 7 Dr. David
Video Solution 8 WhyMath
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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