2010 AMC 8 Problems/Problem 14: Difference between revisions

Revision as of 14:23, 15 August 2021

What is the sum of the prime factors of $2010$ ?

$\textbf{(A)}\ 67\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 77\qquad\textbf{(D)}\ 201\qquad\textbf{(E)}\ 210$

First, we must find the prime factorization of $2010$ . $2010=2\cdot 3 \cdot 5 \cdot 67$ . We add the factors up to get $\boxed{\textbf{(C)}\ 77}$

2010 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 13	Followed by Problem 15
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All AJHSME/AMC 8 Problems and Solutions

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 ==Solution==
-First, we must find the prime factorization of 2010 2010=2*3*5*67 We add the factors up to get C:77
+First, we must find the prime factorization of <math>2010</math>. <math>2010=2\cdot 3 \cdot 5 \cdot 67</math>. We add the factors up to get <math>\boxed{\textbf{(C)}\ 77}</math>
 ==Video Solution==