1962 AHSME Problems/Problem 2: Difference between revisions
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==Problem== | ==Problem== | ||
The expression <math>\sqrt{\frac{4}{3}} - \sqrt{\frac{3}{4}</math> is equal to: | The expression <math>\sqrt{\frac{4}{3}} - \sqrt{\frac{3}{4}}</math> is equal to: | ||
<math> \textbf{(A)}\ \frac{\sqrt{3}}{6}\qquad\textbf{(B)}\ \frac{-\sqrt{3}}{6}\qquad\textbf{(C)}\ \frac{\sqrt{-3}}{6}\qquad\textbf{(D)}\ \frac{5\sqrt{3}}{6}\qquad\textbf{(E)}\ 1 </math> | <math> \textbf{(A)}\ \frac{\sqrt{3}}{6}\qquad\textbf{(B)}\ \frac{-\sqrt{3}}{6}\qquad\textbf{(C)}\ \frac{\sqrt{-3}}{6}\qquad\textbf{(D)}\ \frac{5\sqrt{3}}{6}\qquad\textbf{(E)}\ 1 </math> | ||
==Solution== | ==Solution== | ||
Simplifying <math>\sqrt{\dfrac{4}{3}}</math> yields <math>\dfrac{2}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}</math>. | |||
Simplifying <math>\sqrt{\dfrac{3}{4}}</math> yields <math>\dfrac{\sqrt{3}}{2}</math>. | |||
<math>\dfrac{2\sqrt{3}}{3}-\dfrac{\sqrt{3}}{2}=\dfrac{4\sqrt{3}}{6}-\dfrac{3\sqrt{3}}{6}=\dfrac{\sqrt{3}}{6}</math>. | |||
Since we cannot simplify further, the correct answer is <math>\boxed{\textbf{(A)}\ \frac{\sqrt{3}}{6}}</math> | |||
==See Also== | |||
{{AHSME 40p box|year=1962|before=Problem 1|num-a=3}} | |||
[[Category:Introductory Algebra Problems]] | |||
{{MAA Notice}} | |||
Latest revision as of 21:45, 26 December 2015
Problem
The expression
is equal to:
Solution
Simplifying
yields
.
Simplifying
yields
.
.
Since we cannot simplify further, the correct answer is
See Also
| 1962 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
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| All AHSME Problems and Solutions | ||
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