2024 AMC 10B Problems/Problem 2: Difference between revisions
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{{duplicate|[[2024 AMC 10B Problems/Problem 2|2024 AMC 10B #2]] and [[2024 AMC 12B Problems/Problem 2|2024 AMC 12B #2]]}} | |||
==Problem== | |||
What is <math>10! - 7! \cdot 6!</math> | |||
( | <math>\textbf{(A) } -120 \qquad\textbf{(B) } 0 \qquad\textbf{(C) } 120 \qquad\textbf{(D) } 600 \qquad\textbf{(E) } 720</math> | ||
[ONLY FOR CERTAIN CHINESE TESTPAPERS] | |||
What is <math>10! - 7! \cdot 6! - 5!</math> | |||
<math>\textbf{(A) } -120 \qquad\textbf{(B) } 0 \qquad\textbf{(C) } 120 \qquad\textbf{(D) } 600 \qquad\textbf{(E) } 720</math> | |||
==Solution 1== | |||
<math>10! = 10 \cdot 9 \cdot 8 \cdot 7! = 720 \cdot 7!</math> | |||
<math>6! \cdot 7! = 720 \cdot 7!</math> | |||
Therefore, the equation is equal to <math>720 \cdot 7! - 720 \cdot 7! = \boxed{\textbf{(B) }0}</math> | |||
[ONLY FOR CERTAIN CHINESE TESTPAPERS] | |||
<math>0 - 5! = \boxed{\textbf{(A) }-120}</math> | |||
~Aray10 (Main Solution) and RULE101 (Modifications for certain China test papers) | |||
==Solution 2== | |||
Factoring out <math>7!</math> gives <cmath>7!(10\cdot9\cdot8-1\cdot6!).</cmath> Since <math>10\cdot9\cdot8=6!=720</math>, the answer is <math>\boxed{\text{(B) }0}</math> | |||
Factoring <math>6!</math> also works, it just makes the expression in the parenthesis a little harder to compute. | |||
==Solution 3== | |||
Note that <math>10! - 7! \cdot 6!</math> must be divisible by <math>7</math>, and <math>\boxed{\text{(B) }0}</math> is the only option divisible by <math>7</math>. | |||
==Solution 4== | |||
<math>10! - 7! \cdot 6!</math> can be split into two parts, <math>10!</math> and <math>7! \cdot 6!</math>. | |||
We can break the <math>6!</math> into <math>(2 \cdot 4)(3 \cdot 5 \cdot 6)</math> | |||
The <math>2 \cdot 4</math> part makes <math>8</math>, and the <math>3 \cdot 5 \cdot 6</math> part makes <math>90</math>, which is <math>9 \cdot 10</math>. | |||
We still have the 7!, and we can multiply it by <math>8 \cdot 9 \cdot 10</math>. This is clearly equivalent to <math>10!</math>, so our solution is <math>10! - 10! = </math><math>\boxed{\text{(B) }0}</math>. | |||
==Solution 5== | |||
<math>10! = 3,628,800</math>, <math>7! = 5,040</math>, and <math>6! = 720</math>. Of course, if you're fast enough, you can do <math>5,040 \cdot 720 = 3,628,800</math>. Therefore, <math>3,628,800 - 3,628,800 = \boxed{\text{(B) }0}</math>. | |||
-pepper2831 | |||
==Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)== | |||
https://youtu.be/DIl3rLQQkQQ?feature=shared | |||
~ Pi Academy | |||
==Video Solution 2 by SpreadTheMathLove== | |||
https://www.youtube.com/watch?v=24EZaeAThuE | |||
== Video Solution by Daily Dose of Math == | |||
https://youtu.be/DVlOz24jWuo | |||
~Thesmartgreekmathdude | |||
==Video Solution by the BeautyofMath== | |||
https://youtu.be/mpnm_r6D3-w?t=373 | |||
~IceMatrix | |||
==See also== | |||
{{AMC10 box|year=2024|ab=B|num-b=1|num-a=3}} | |||
{{AMC12 box|year=2024|ab=B|num-b=1|num-a=3}} | |||
{{MAA Notice}} | |||
Latest revision as of 21:10, 6 October 2025
- The following problem is from both the 2024 AMC 10B #2 and 2024 AMC 12B #2, so both problems redirect to this page.
Problem
What is
[ONLY FOR CERTAIN CHINESE TESTPAPERS]
What is
Solution 1
Therefore, the equation is equal to
[ONLY FOR CERTAIN CHINESE TESTPAPERS]
~Aray10 (Main Solution) and RULE101 (Modifications for certain China test papers)
Solution 2
Factoring out
gives
Since
, the answer is
Factoring
also works, it just makes the expression in the parenthesis a little harder to compute.
Solution 3
Note that
must be divisible by
, and
is the only option divisible by
.
Solution 4
can be split into two parts,
and
.
We can break the
into
The
part makes
, and the
part makes
, which is
.
We still have the 7!, and we can multiply it by
. This is clearly equivalent to
, so our solution is ![]()
.
Solution 5
,
, and
. Of course, if you're fast enough, you can do
. Therefore,
.
-pepper2831
Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)
https://youtu.be/DIl3rLQQkQQ?feature=shared
~ Pi Academy
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=24EZaeAThuE
Video Solution by Daily Dose of Math
~Thesmartgreekmathdude
Video Solution by the BeautyofMath
https://youtu.be/mpnm_r6D3-w?t=373
~IceMatrix
See also
| 2024 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2024 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing