2007 iTest Problems/Problem 11: Difference between revisions
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== Problem 11 == | == Problem 11 == | ||
Consider the "tower of power" <math>2^{2^{2^{\cdot^{\cdot^\cdot^{2}}}}}</math>, where there are 2007 twos including the base. What is the last (units digit) of this number? | Consider the "tower of power" <math>2^{2^{2^{\cdot^{\cdot^{\cdot^{2}}}}}}</math>, where there are 2007 twos including the base. What is the last (units digit) of this number? | ||
<math>\text{(A) }0\qquad | <math>\text{(A) }0\qquad | ||
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== Solution == | == Solution == | ||
Note that <math>2^1 = 2</math>, <math>2^2 = 4</math>, <math>2^3 = 8</math>, <math>2^4 = 16</math>, and <math>2^5 = 32</math>. The units digit of <math>2^n</math> cycle every time <math>n</math> is increased by <math>4</math>. | |||
Since <math>2^{2^{2^{\cdot^{\cdot^{\cdot^{2}}}}}}</math> with <math>2006</math> twos is a multiple of four, the units digit is <math>\boxed{\textbf{(G) }6}</math>. | |||
==See Also== | |||
{{iTest box|year=2007|num-b=10|num-a=12}} | |||
[[Category:Introductory Number Theory Problems]] | |||
Latest revision as of 03:31, 10 June 2018
Problem 11
Consider the "tower of power"
, where there are 2007 twos including the base. What is the last (units digit) of this number?
Solution
Note that
,
,
,
, and
. The units digit of
cycle every time
is increased by
.
Since
with
twos is a multiple of four, the units digit is
.
See Also
| 2007 iTest (Problems, Answer Key) | ||
| Preceded by: Problem 10 |
Followed by: Problem 12 | |
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