2001 AMC 10 Problems/Problem 3: Difference between revisions

Latest revision as of 20:48, 25 August 2011

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-== Solution ==
+#redirect [[2001 AMC 12 Problems/Problem 1]]
-The sum of the two numbers is <math> S </math>. If <math> 3 </math> is added to each number, then you basically added <math> 6 </math> to <math> S </math>.
-When you double the resulting expression,
-<math> 2(S+6) = \textbf{(E) }2S+12 </math>
-== See Also ==
-{{AMC10 box|year=2001|num-b=2|num-a=4}}