Art of Problem Solving

2001 AMC 10 Problems/Problem 3: Difference between revisions

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== Problem ==
#redirect [[2001 AMC 12 Problems/Problem 1]]
 
The sum of two numbers is <math> S </math>. Suppose <math> 3 </math> is added to each number and then each of the resulting numbers is doubled. What is the sum of the final two numbers?
 
<math> \mathrm{(A)}\ 2S+3 \qquad\mathrm{(B)}\ 3S+2 \qquad\mathrm{(C)}\ 3S+6 \qquad\mathrm{(D)}\ 2S+6 \qquad\mathrm{(E)}\ 2S+12 </math>
 
== Solution ==
 
The sum of the two numbers is <math> S </math>. If <math> 3 </math> is added to each number, then you basically added <math> 6 </math> to <math> S </math>.
 
When you double the resulting expression,
 
<math> 2(S+6) = \textbf{(E) }2S+12 </math>
 
== See Also ==
 
{{AMC10 box|year=2001|num-b=2|num-a=4}}

Latest revision as of 20:48, 25 August 2011