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2020 AMC 8 Problems/Problem 2: Difference between revisions

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==Problem 2==
==Problem==
Four friends do yardwork for their neighbors over the weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned <math>\$40</math> give to the others?
Four friends do yardwork for their neighbors over the weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. They decide to split their earnings equally among themselves. In total, how much will the friend who earned <math>\$40</math> give to the others?


<math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>
<math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>


==Solution==
==Solution==
First we average <math>15,20,25,40</math> to get <math>25</math>. Thus, <math>40 - 25 = \boxed{\textbf{(C) }\$15.}</math>. ~~Spaced_Out
The friends earn <math>\$\left(15+20+25+40\right)=\$100</math> in total. Since they decided to split their earnings equally, it follows that each person will get <math>\$\left(\frac{100}{4}\right)=\$25</math>. Since the friend who earned <math>\$40</math> will need to leave with <math>\$25</math>, he will have to give <math>\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}</math> to the others.


==Solution 2==
==Video Solution by NiuniuMaths (Easy to understand!)==
The total earnings for the four friends is <math>\$15+\$20+\$25+\$40=\$100</math>. Since they decided to split their earnings equally among themselves, it follows that each person will get <math>\frac{\$100}{4}=\$25</math>. Since the friend who earned <math>\$40</math> will need to leave with <math>\$25</math>, he will have to give <math>\$40-\$25=\$15</math> to the others <math>\implies\boxed{\textbf{(C) }\$15}</math>.<br>
https://www.youtube.com/watch?v=8hgK6rESdek&t=9s
~[http://artofproblemsolving.com/community/user/jmansuri junaidmansuri]


==See also==  
~NiuniuMaths
 
 
==Video Solution by Math-X (First understand the problem!!!)==
https://youtu.be/UnVo6jZ3Wnk?si=UKNnVW0qEuIdyt8u&t=229
 
~Math-X
 
==Video Solution (🚀Just 1 min🚀)==
https://youtu.be/CC5jRJ95QB0
 
~Education, the Study of Everything
 
==Video Solution by WhyMath==
https://youtu.be/-mSgttsOv2Y
 
~savannahsolver
 
==Video Solution by The Learning Royal==
https://youtu.be/eSxzI8P9_h8
 
~The Learning Royal
 
==Video Solution by Interstigation==
https://youtu.be/YnwkBZTv5Fw?t=62
 
~Interstigation
 
==Video Solution by North America Math Contest Go Go Go==
https://www.youtube.com/watch?v=ZwfPEYd55NQ
 
~North America Math Contest Go Go Go
 
==Video Solution by STEMbreezy==
https://youtu.be/L_vDc-i585o?list=PLFcinOE4FNL0TkI-_yKVEYyA_QCS9mBNS&t=37
 
~STEMbreezy
 
== Video solution by TheNeuralMathAcademy ==
https://youtu.be/mGQw1yALXYM&t=113s
 
==See Also==  
{{AMC8 box|year=2020|num-b=1|num-a=3}}
{{AMC8 box|year=2020|num-b=1|num-a=3}}
{{MAA Notice}}
{{MAA Notice}}
[[Category:Introductory Algebra Problems]]

Latest revision as of 23:46, 20 August 2025

Problem

Four friends do yardwork for their neighbors over the weekend, earning $\$15, \$20, \$25,$ and $\$40,$ respectively. They decide to split their earnings equally among themselves. In total, how much will the friend who earned $\$40$ give to the others?

$\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25$

Solution

The friends earn $\$\left(15+20+25+40\right)=\$100$ in total. Since they decided to split their earnings equally, it follows that each person will get $\$\left(\frac{100}{4}\right)=\$25$. Since the friend who earned $\$40$ will need to leave with $\$25$, he will have to give $\$\left(40-25\right)=\boxed{\textbf{(C) }\$15}$ to the others.

Video Solution by NiuniuMaths (Easy to understand!)

https://www.youtube.com/watch?v=8hgK6rESdek&t=9s

~NiuniuMaths


Video Solution by Math-X (First understand the problem!!!)

https://youtu.be/UnVo6jZ3Wnk?si=UKNnVW0qEuIdyt8u&t=229

~Math-X

Video Solution (🚀Just 1 min🚀)

https://youtu.be/CC5jRJ95QB0

~Education, the Study of Everything

Video Solution by WhyMath

https://youtu.be/-mSgttsOv2Y

~savannahsolver

Video Solution by The Learning Royal

https://youtu.be/eSxzI8P9_h8

~The Learning Royal

Video Solution by Interstigation

https://youtu.be/YnwkBZTv5Fw?t=62

~Interstigation

Video Solution by North America Math Contest Go Go Go

https://www.youtube.com/watch?v=ZwfPEYd55NQ

~North America Math Contest Go Go Go

Video Solution by STEMbreezy

https://youtu.be/L_vDc-i585o?list=PLFcinOE4FNL0TkI-_yKVEYyA_QCS9mBNS&t=37

~STEMbreezy

Video solution by TheNeuralMathAcademy

https://youtu.be/mGQw1yALXYM&t=113s

See Also

2020 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 1 		Followed by
Problem 3
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All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing

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