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2016 AMC 8 Problems/Problem 9: Difference between revisions

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== Problem ==
What is the sum of the distinct prime integer divisors of <math>2016</math>?
What is the sum of the distinct prime integer divisors of <math>2016</math>?


<math>\textbf{(A) }9\qquad\textbf{(B) }12\qquad\textbf{(C) }16\qquad\textbf{(D) }49\qquad \textbf{(E) }63</math>
<math>\textbf{(A) }9\qquad\textbf{(B) }12\qquad\textbf{(C) }16\qquad\textbf{(D) }49\qquad \textbf{(E) }63</math>


==Solution==
==Solutions==
 
===Solution 1===


The prime factorization is <math>2016=2^5\times3^2\times7</math>.  Since the problem is only asking us for the distinct prime factors, we have <math>2,3,7</math>.  Their desired sum is then <math>\boxed{\textbf{(B) }12}</math>.
The prime factorization is <math>2016=2^5\times3^2\times7</math>.  Since the problem is only asking us for the distinct prime factors, we have <math>2,3,7</math>.  Their desired sum is then <math>\boxed{\textbf{(B) }12}</math>.
==Video Solution==
https://youtu.be/I_jevKp3Kyg?si=qKDYbUmjFkioeIvE
~Elijahman~
==Video Solution (CREATIVE THINKING!!!)==
https://youtu.be/GNFnta9MF9E
~Education, the Study of Everything
==Video Solution==
https://youtu.be/1KN7OTG3k-0
~savannahsolver
==See Also==
{{AMC8 box|year=2016|num-b=8|num-a=10}}
{{MAA Notice}}
[[Category:Introductory Number Theory Problems]]

Latest revision as of 17:04, 25 June 2025

Problem

What is the sum of the distinct prime integer divisors of $2016$?

$\textbf{(A) }9\qquad\textbf{(B) }12\qquad\textbf{(C) }16\qquad\textbf{(D) }49\qquad \textbf{(E) }63$

Solutions

Solution 1

The prime factorization is $2016=2^5\times3^2\times7$. Since the problem is only asking us for the distinct prime factors, we have $2,3,7$. Their desired sum is then $\boxed{\textbf{(B) }12}$.

Video Solution

https://youtu.be/I_jevKp3Kyg?si=qKDYbUmjFkioeIvE

~Elijahman~

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/GNFnta9MF9E

~Education, the Study of Everything

Video Solution

https://youtu.be/1KN7OTG3k-0

~savannahsolver

See Also

2016 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing