2008 AMC 8 Problems/Problem 19: Difference between revisions
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==Solution 2== | ==Solution 2== | ||
Arbitrarily pick a point in the grid. Clearly, we see two options for the other point to be placed, so the answer is <math>\boxed{\textbf{(B)}\ \frac27}</math> | Arbitrarily pick a point in the grid. Clearly, we see two options for the other point to be placed, so the answer is <math>\boxed{\textbf{(B)}\ \frac27}</math>. | ||
==Video Solution== | |||
https://www.youtube.com/watch?v=ZVD_PZYjonQ ~David | |||
==Video Solution 2== | |||
https://youtu.be/PeI8YSHCdlM Soo, DRMS, NM | |||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|num-b=18|num-a=20}} | {{AMC8 box|year=2008|num-b=18|num-a=20}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 13:53, 30 December 2024
Problem
Eight points are spaced around at intervals of one unit around a
square, as shown. Two of the
points are chosen at random. What is the probability that the two points are one unit apart?
Solution 1
The two points are one unit apart at
places around the edge of the square. There are ![]()
ways to choose two points. The probability is
Solution 2
Arbitrarily pick a point in the grid. Clearly, we see two options for the other point to be placed, so the answer is
.
Video Solution
https://www.youtube.com/watch?v=ZVD_PZYjonQ ~David
Video Solution 2
https://youtu.be/PeI8YSHCdlM Soo, DRMS, NM
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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