2009 AMC 8 Problems/Problem 7: Difference between revisions

Latest revision as of 07:23, 30 May 2023

Problem

The triangular plot of ACD lies between Aspen Road, Brown Road and a railroad. Main Street runs east and west, and the railroad runs north and south. The numbers in the diagram indicate distances in miles. The width of the railroad track can be ignored. How many square miles are in the plot of land ACD?

$[asy] size(250); defaultpen(linewidth(0.55)); pair A=(-6,0), B=origin, C=(0,6), D=(0,12); pair ac=C+2.828*dir(45), ca=A+2.828*dir(225), ad=D+2.828*dir(A--D), da=A+2.828*dir(D--A), ab=(2.828,0), ba=(-6-2.828, 0); fill(A--C--D--cycle, gray); draw(ba--ab); draw(ac--ca); draw(ad--da); draw((0,-1)--(0,15)); draw((1/3, -1)--(1/3, 15)); int i; for(i=1; i<15; i=i+1) { draw((-1/10, i)--(13/30, i)); } label("$A$", A, SE); label("$B$", B, SE); label("$C$", C, SE); label("$D$", D, SE); label("$3$", (1/3,3), E); label("$3$", (1/3,9), E); label("$3$", (-3,0), S); label("Main", (-3,0), N); label(rotate(45)*"Aspen", A--C, SE); label(rotate(63.43494882)*"Brown", A--D, NW); [/asy]$

$\textbf{(A)}\ 2\qquad \textbf{(B)}\ 3 \qquad \textbf{(C)}\ 4.5 \qquad \textbf{(D)}\ 6 \qquad \textbf{(E)}\ 9$

Solution

The area of a triangle is $\frac12 bh$ . If we let $CD$ be the base of the triangle, then the height is $AB$ , and the area is $\frac12 \cdot 3 \cdot 3 = \boxed{\textbf{(C)}\ 4.5}$ .

Solution 2

We can see that there is a big triangle encasing $ACD$ . The area of that triangle is $\frac12 \cdot 3 \cdot 6 = 9$ . We can easily see that triangle $ABC$ is $\frac12 \cdot 3 \cdot 3$ , which is $4.5$ . $9-4.5$ is $4.5$ , so the answer is $\boxed{\textbf{(C)}\ 4.5}$ .

Video Solution

https://www.youtube.com/watch?v=Opz71P5o4uI ~David

Video Solution by OmegaLearn

https://youtu.be/j3QSD5eDpzU?t=158

~ pi_is_3.14

Video Solution by WhyMath

https://youtu.be/QfQIqS60m5s

~savannahsolver

2009 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 6	Followed by Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing

@@ Line 46: / Line 46: @@
 ==Video Solution==
-https://www.youtube.com/watch?v=Opz71P5o4uI
+https://www.youtube.com/watch?v=Opz71P5o4uI  ~David
 ==Video Solution by OmegaLearn==
@@ Line 52: / Line 52: @@
 ~ pi_is_3.14
+==Video Solution by WhyMath==
+https://youtu.be/QfQIqS60m5s
+~savannahsolver
 ==See Also==
 {{AMC8 box|year=2009|num-b=6|num-a=8}}
 {{MAA Notice}}

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