2010 AMC 10A Problems/Problem 1: Difference between revisions
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== Problem 1 == | |||
Mary's top book shelf holds five books with the following widths, in centimeters: <math>6</math>, <math>\dfrac{1}{2}</math>, <math>1</math>, <math>2.5</math>, and <math>10</math>. What is the average book width, in centimeters? | |||
<math> | |||
\mathrm{(A)}\ 1 | |||
\qquad | |||
\mathrm{(B)}\ 2 | |||
\qquad | |||
\mathrm{(C)}\ 3 | |||
\qquad | |||
\mathrm{(D)}\ 4 | |||
\qquad | |||
\mathrm{(E)}\ 5 | |||
</math> | |||
==Solution== | ==Solution== | ||
| Line 4: | Line 19: | ||
To find the average, we add up the widths <math>6</math>, <math>\dfrac{1}{2}</math>, <math>1</math>, <math>2.5</math>, and <math>10</math>, to get a total sum of <math>20</math>. Since there are <math>5</math> books, the average book width is <math>\frac{20}{5}=4</math> The answer is <math>\boxed{D}</math>. | To find the average, we add up the widths <math>6</math>, <math>\dfrac{1}{2}</math>, <math>1</math>, <math>2.5</math>, and <math>10</math>, to get a total sum of <math>20</math>. Since there are <math>5</math> books, the average book width is <math>\frac{20}{5}=4</math> The answer is <math>\boxed{D}</math>. | ||
==Video Solution== | |||
https://youtu.be/C1VCk_9A2KE | |||
~IceMatrix | |||
== See Also == | |||
{{AMC10 box|year=2010|ab=A|before=Non-Existent|num-a=2}} | |||
{{MAA Notice}} | |||
Latest revision as of 16:12, 18 October 2021
Problem 1
Mary's top book shelf holds five books with the following widths, in centimeters: 
, 
, 
, 
, and 
. What is the average book width, in centimeters?
Solution
To find the average, we add up the widths , , , , and , to get a total sum of 
. Since there are 
books, the average book width is 
The answer is 
.
Video Solution
~IceMatrix
See Also
| 2010 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Non-Existent |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions. Error creating thumbnail: File missing
