11 August 2020

• curprev 11:0111:01, 11 August 2020 Rocketsri talk contribs m 7,964 bytes 0 →Solution 3 -hashtagmath

23 February 2019

• curprev 14:3414:34, 23 February 2019 Hashtagmath talk contribs m 7,964 bytes −16 →Solution 2 (but elaborated)-hashtagmath

17 February 2019

• curprev 02:5502:55, 17 February 2019 Hashtagmath talk contribs 7,980 bytes +6,200 →Solution

11 February 2019

• curprev 12:3012:30, 11 February 2019 Hashtagmath talk contribs m 1,780 bytes +7 →Solution 1

28 January 2019

• curprev 16:5116:51, 28 January 2019 Onezero talk contribs 1,773 bytes −2,186 →Solution 3 (Very long and detailed)

15 August 2017

• curprev 22:1922:19, 15 August 2017 Onezero talk contribs 3,959 bytes +2,186 →Solution

20 July 2016

• curprev 08:2908:29, 20 July 2016 1=2 talk contribs m 1,773 bytes +3 →See Also
• curprev 08:2308:23, 20 July 2016 1=2 talk contribs 1,770 bytes +126 Reconstructed from page template

5 June 2014

• curprev 22:5522:55, 5 June 2014 Suli talk contribs 1,644 bytes −40 →Solution 2
• curprev 22:5222:52, 5 June 2014 Suli talk contribs 1,684 bytes +836 →Solution

7 April 2014

• curprev 20:5220:52, 7 April 2014 Suli talk contribs 848 bytes −21 No edit summary

4 July 2013

• curprev 12:3212:32, 4 July 2013 Nathan wailes talk contribs 869 bytes +15 No edit summary

6 November 2012

• curprev 10:2310:23, 6 November 2012 Zhuangzhuang talk contribs m 854 bytes +1 No edit summary
• curprev 10:2110:21, 6 November 2012 Zhuangzhuang talk contribs m 853 bytes +16 No edit summary

4 November 2012

• curprev 20:5120:51, 4 November 2012 Zhuangzhuang talk contribs 837 bytes +4 No edit summary
• curprev 20:5020:50, 4 November 2012 Zhuangzhuang talk contribs 833 bytes +124 No edit summary
• curprev 20:4820:48, 4 November 2012 Zhuangzhuang talk contribs 709 bytes +43 No edit summary
• curprev 20:4620:46, 4 November 2012 Zhuangzhuang talk contribs 666 bytes +666 Created page with "First, as <math>180\sin{180^\circ}=0,</math> we omit that term. Now, we multiply by <math>\sin 1^\circ</math> to get, after using product to sum, <math>(\cos 1^\circ-\cos 3^\circ..."